dsdxlibt98300 2015-11-05 18:42
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带属性的JSON序列化和XML

I have an array that needs to be serialized to either JSON or XML depending on the requested content type.

    $responseArray = [
                          "name" => ""
                        , "status" => -1
                        , "message" =>  "An unknown error has occurred."
                    ];

Encoding it with JSON works just fine

$plainTextResponse = $serializer->serialize($responseArray, 'json');

{"name":"","status":-1,"message":"An unknown error has occurred."}

Which is right and exactly what I need. The problem is representing it as XML

$plainTextResponse = $serializer->serialize($responseArray, 'xml');

<?xml version="1.0"?>
<response>
    <name></name>
    <status>-1</status>
    <message>An unknown error has occurred.</message>
</response>

But intead of nesting those properties under command I need them to appear as attributes. That is doable this way (notice the @ before attribute names)

    $responseArray = [
                          "@name" => ""
                        , "@status" => -1
                        , "@message" =>  "An unknown error has occurred."
                     ];

...

    $plainTextResponse = $serializer->serialize($responseArray, 'xml');


<?xml version="1.0"?>
<response name="" status="-1" message="An unknown error has occurred."/>

And obviously if I try to convert that to JSON then it will leave those @ in the names of the attributes

$plainTextResponse = $serializer->serialize($responseArray, 'json');

{"@name":"","@status":-1,"@message":"An unknown error has occurred."}

Is there a way to serialise an array so that it adds attributes in XML and does not have @ in json?

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1条回答 默认 最新

  • dtjpz48440 2015-11-05 18:58
    关注

    I think you should create another array for xml serialization:

    foreach($responseArray as $key => $value) {
        $respondeArrayXml["@".$key] = $value;
    }
    $plainTextResponseXML = $serializer->serialize($responseArrayXML, 'xml');
    $plainTextResponseJSON = $serializer->serialize($responseArray, 'json');
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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