dongwanqiang_2017 2016-04-28 08:30
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使用正则表达式从引号之间提取值

I have the following string:

feature name="osp"

I need to extract part of the strings out and put them into a new string. The word feature can change and the word inside quotes can change so I need to be able to capture any instance possible. The name=" " part is always the same. The result I need is:

feature osp

I need to filter out the name= and quotes from the string.

I've used this ^\w*\s to get the first feature part but can't figure out how to extract osp from the string using a regex. I've been looking here RegEx: Grabbing values between quotation marks but can't get a regex that combines both to get the result I need. I'm working in PHP so using preg-match at the moment. Can anyone help with this?

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  • duanpuchun5275 2016-04-28 08:51
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    I'd go with

    (\w+)\s+name\s*=\s*"([^"]*)
    

    It's a little bit slower, but it allows for arbitrary number of spaces and it captures the first word correctly, even with Alexandru's test.

    See it work here at regex101.

    Regards

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