在PHP中的javascript函数中显示数据库的行值

Question

$finalval=0;
while($row = mysql_fetch_array($result))
{
 $finalval=$finalval. "<a href='#' 
 onClick='showContent(".json_encode($row['ID']).")'>".  $row['Title'] . "</a> <br>" ;

}
echo  $finalval;

<script language="javascript" type="text/javascript"  >
 function showContent(value)
 {
 alert(value);
 }
</script>

Please rectify my error alert box is displaying null instead of ID value.Thanks

Answer 1

You don't need to Json_encode just

'showContent(".$row['ID'].")'

I would also suggest you to check your source code in your browser if this doesnt work and see what it prints in showcontent(). I think you are not getting any value in $row['ID']. Again check source code in your browser by right clicking in browser and clicking view source code and check there your showcontent() function and see what value is there