douyaju4259 2012-08-23 07:45
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在if语句中定义值不起作用

I'm working on an easy way to do edit the status of an Paypal payment system so i can switch it over in test mode when needed without going into the code. "MODULE_PAYMENT_PAYPAL_STANDARD_GATEWAY_SERVER" is defined to "Live", but for some reason it keep throwing the sandbox url.

echo MODULE_PAYMENT_PAYPAL_STANDARD_GATEWAY_SERVER ;

if (MODULE_PAYMENT_PAYPAL_STANDARD_GATEWAY_SERVER == "Live") {
    $form_action_url = 'https://www.paypal.com/cgi-bin/webscr';
  } else {
    $form_action_url = 'https://www.sandbox.paypal.com/cgi-bin/webscr';
  }
echo ' '.$form_action_url;
die();

The above outputs:

Live https://www.sandbox.paypal.com/cgi-bin/webscr'

If I replace MODULE_PAYMENT_PAYPAL_STANDARD_GATEWAY_SERVER with 'live' it returns the value correctly, I also tried to move the DEFINE to a Variable before it goes to the IF statement, but it still doesn't work.

I'm using OsCommerce to define this via the admin system.

var_dump also shows:

string(20) "Live"

instead of what it should:

string(4) "Live"

Options for MODULE_PAYMENT_PAYPAL_STANDARD_GATEWAY_SERVER is "Live" and "Sandbox".

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3条回答 默认 最新

  • dongpangzan6425 2012-08-23 12:16
    关注

    After removing and adding MODULE_PAYMENT_PAYPAL_STANDARD_GATEWAY_SERVER a few times without any changes I completely removed the paypal script from the site and installet it again. now it works!

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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