从内容处置标题获取UTF-8文件名

Question

When I try to get the filename from the Content-Disposition Header the go function mime.ParseMediaType() fails with the error mime: invalid media parameter

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I already found out, that it works with the normal filename format:

attachment; filename="Geotag_Stamp%20(1)%20(1).jpg" <- works

But with the UTF-8 filename (defined in rfc6266) it failes with the error given in the first paragraph:

attachment; filename*=UTF-8''"Geotag_Stamp%20(1)%20(1).jpg" <- Fails

---

Here is my code:

package main

import (
    "fmt"
    "mime"
)

func main() {
    d, params, err := mime.ParseMediaType(`attachment; filename="Geotag_Stamp%20(1)%20(1).jpg"`)
    if err != nil {
        fmt.Println("**Normal Filename error:", err)
    }

    fmt.Println("Normal:", d, params)
    d, params, err = mime.ParseMediaType(`attachment; filename*=UTF-8''"Geotag_Stamp%20(1)%20(1).jpg"`)
    if err != nil {
        fmt.Println("**UTF-8 Filename error:", err)
    }
    fmt.Println("UTF-8",d, params)
}

On the playground

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Is it possible that the stdlib does not support the UTF-8 version of Content-Disposition->Filename ?

Answer 1

The quotes must surround the header value:

attachment; filename*="UTF-8''Geotag_Stamp%20(1)%20(1).jpg"

Run it on the playground