将IP"1.1.168.192"
变换成 IP"192.168.1.1"
只改""内的
返回string类型
1条回答
- threenewbee 2018-10-11 10:50关注
#include <vector> #include <string> #include <iostream> using namespace std; vector<string> split(const string &s, const string &seperator){ vector<string> result; typedef string::size_type string_size; string_size i = 0; while(i != s.size()){ //找到字符串中首个不等于分隔符的字母; int flag = 0; while(i != s.size() && flag == 0){ flag = 1; for(string_size x = 0; x < seperator.size(); ++x) if(s[i] == seperator[x]){ ++i; flag = 0; break; } } //找到又一个分隔符,将两个分隔符之间的字符串取出; flag = 0; string_size j = i; while(j != s.size() && flag == 0){ for(string_size x = 0; x < seperator.size(); ++x) if(s[j] == seperator[x]){ flag = 1; break; } if(flag == 0) ++j; } if(i != j){ result.push_back(s.substr(i, j-i)); i = j; } } return result; } int main() { string s = "1.1.168.192"; vector<string> v = split(s, "."); string result = v[v.size() - 1]; for(vector<string>::size_type i = v.size() - 2; i >= 0; i--) { result = result + "."; result = result + v[i]; } cout << result; }
192.168.1.1
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