关于列表运算的一些运算有报错不知道咋解决

Question

A = ((df['a'][-1:] + df['a'][1:])/2)

B = ((df['a'][-1:]+df['b'][-1:]+df['b'][-1:]+df['d'][-1:])/4)

if A < B

print(1)

 

ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().

Answer 1

改成这样，要有冒号，下面的语句要缩进，AB转成float类型，哪里不明白可以再问我

A = float(((df['a'][-1:] + df['a'][1:])/2))
B = float(((df['a'][-1:]+df['b'][-1:]+df['b'][-1:]+df['d'][-1:])/4))
if A < B:
    print(1)

报错是说参数不明确，可能是浮点型、整型或者对象。这就是问题的所在，转换类型float再试试