SELECT T.*,
'个人客户' ERROR_TWO_TYPE
FROM (SELECT *
FROM SRBZ_HIVE.TMP_YWJH_ZQZRR_GR_02 A
WHERE EXISTS (SELECT *
FROM (SELECT CERTI_NUMBER,
COUNT(DISTINCT B.CUST_NAME)
FROM IWC_DWD.DWD_CRM_CUST_DAY B
WHERE B.STATUS_CD = '1000'
AND B.P_DAY_ID = '${date_no}'
GROUP BY B.CERTI_NUMBER
HAVING COUNT(DISTINCT B.CUST_NAME) > 1) C
WHERE C.CERTI_NUMBER = A.CERTI_NUMBER)) T
WHERE NOT EXISTS (SELECT *
FROM SRBZ_HIVE.C_IDCARD_VERIFY C
WHERE T.CERTI_NUMBER = C.IDCARD_NO
AND T.CUST_NAME = C.IDCARD_NAME)
AND NOT EXISTS
(SELECT *
FROM SRBZ_HIVE.IDENTIFY_CARD_INFO TT
WHERE T.CERTI_NUMBER = TT.IDENTIFY_CARD_ID
AND T.CUST_NAME = TT.NAME)
AND (T.REAL_FLAG <> 'T' OR T.REAL_FLAG IS NULL)
hive脚本把exists或not exist改成inner join或left join
- 写回答
- 好问题 0 提建议
- 追加酬金
- 关注问题
- 邀请回答
-
1条回答 默认 最新
- bj_0163_bj 2022-04-29 20:40关注
SELECT T.*, '个人客户' ERROR_TWO_TYPE FROM (SELECT * FROM SRBZ_HIVE.TMP_YWJH_ZQZRR_GR_02 A inner join (SELECT CERTI_NUMBER, COUNT(DISTINCT B.CUST_NAME) FROM IWC_DWD.DWD_CRM_CUST_DAY B WHERE B.STATUS_CD = '1000' AND B.P_DAY_ID = '${date_no}' GROUP BY B.CERTI_NUMBER HAVING COUNT(DISTINCT B.CUST_NAME) > 1) C on C.CERTI_NUMBER = A.CERTI_NUMBER) T LEFT JOIN SRBZ_HIVE.C_IDCARD_VERIFY C1 ON T.CERTI_NUMBER = C.IDCARD_NO AND T.CUST_NAME = C.IDCARD_NAME LEFT JOIN SRBZ_HIVE.IDENTIFY_CARD_INFO TT ON T.CERTI_NUMBER = TT.IDENTIFY_CARD_ID AND T.CUST_NAME = TT.NAME WHERE C1.IDCARD_NO IS NULL AND TT.IDENTIFY_CARD_ID IS NULL AND (T.REAL_FLAG <> 'T' OR T.REAL_FLAG IS NULL)
本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报
悬赏问题
- ¥15 Python中的request,如何使用ssr节点,通过代理requests网页。本人在泰国,需要用大陆ip才能玩网页游戏,合法合规。
- ¥15 Oracle触发器记录修改前后的字段值
- ¥100 为什么这个恒流源电路不能恒流?
- ¥15 有偿求跨组件数据流路径图
- ¥15 写一个方法checkPerson,入参实体类Person,出参布尔值
- ¥15 我想咨询一下路面纹理三维点云数据处理的一些问题,上传的坐标文件里是怎么对无序点进行编号的,以及xy坐标在处理的时候是进行整体模型分片处理的吗
- ¥15 CSAPPattacklab
- ¥15 一直显示正在等待HID—ISP
- ¥15 Python turtle 画图
- ¥15 stm32开发clion时遇到的编译问题