douyinmian8151 2012-06-27 17:11
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从目录列出图像(01.png)和描述(01.txt)

How can I display images from directory and get a corresponding description with each image, give the description exists.

in Directory //

01.png
01.txt
02.png 
03.png 
03.txt 
etc.

to display as //

<img src="01.png"><br>This is the description from the text file named 01.txt
<img src="02.png"><br>
<img src="03.png"><br>This is the description from the text file named 03.txt

I've been searching and searching, but can't find anything, so if someone could point me in the right direction it would be greatly appreciated. Also this is a very useful thing to be able to do for people wanting to create very simple galleries or lists of images and names.

Thanks in advance!

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  • doudun2212 2012-06-27 17:18
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    Your question is a bit confusing.

    make an array with all information.

    $pics = array('img' => '01.png', 'text' => 'This is the description');
    
    foreach($pics as $pic) {
        echo '<img src="'.$pic['name'].'" alt="">' . $pic['text'];
    }
    

    So you have to put your information in an array or a database otherwise you cannot map the desciption to your image.

    When you want to read dynamicly the folder its a bit difficult.

    You can look at readdir or glob then you can read all images get the name and load the textfile with file_get_contents but i think its not a really performant way.

    评论

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