dongsan6889 2018-02-01 05:48
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如何在这段代码中创建我期望的json

I have one array using i want to make my json response but i am not able do this:

print_r($exist_email);

    Array
(
    [user_id] => 3
)

I tried like this

$response_array['status']='Exist User';
$response_array['message']='Email already exists.';
$response_array['data']=$exist_email;
$this->response($this->json($response_array), 200);

public function response($data,$status=200){
            $this->_code = ($status)?$status:200;
            $this->set_headers();
            echo $data;
            exit;
        }

protected function json($data){
            if(is_array($data)){
                return json_encode($data);
            }
        }

I am getting response

    {
    "status": "Exist User",
    "message": "Email already exists.",
    "data": {
        "user_id": "3"
    }
}

My expected output

    {
    "status": "Exist User",
    "message": "Email already exists.",
    "data": [
        {
            "user_id": "3"
        }
    ]
}
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4条回答 默认 最新

  • dongqinta4174 2018-02-01 05:54
    关注

    As per my comments you should used multidimensional array in this line $response_array['data']=$exist_email;

    Above line you can replace with below lines

    $response_array['data'][0]=$exist_email;
    

    OR

    $response_array['data'][]=$exist_email;
    

    Here you can check your desired Output

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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