duanrong5167
duanrong5167
2016-02-02 14:28

在$ .post - JQuery中创建动态变量赋值

Could i use dynamic variable inside my $.post JQuery/Ajax code? I would like to know where i am making mistakes or i am misunderstood the useage of $.post of JQuery.

I have dynamically created variables and value assigned to it from text-fields. Now i want to use those variables inside $.post of JQuery.

Code Below:

The part that's working fine:

var boxFields = ["customerId","customerName","customerContact","customerEmail"];
var boxVar = [];

for(var x=0;x<4;x++)
{
    boxVar[x] = $("#" + boxFields[x]).val();
}

alert(boxVar[1]); //Just random call to check it works.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<input type="text" id="customerId" value="12345"/>
<br>
<br>
<input type="text" id="customerName" value="John Doe"/>
<br>
<br>
<input type="text" id="customerContact" value="XXXXXXXXXX"/>
<br>
<br>
<input type="text" id="customerEmail" value="xxxxxx@xxx.com"/>

Now i have dynamically generated variables (check above hidden snippet for that). So to use those in $.post.

Update:

Sorry, for missing the actual part

My Problem/Question: Could i use for loop to create dynamic objects inside $.post.

Whole Code:

var boxFields = ["customerId","customerName","customerContact","customerEmail"];
var boxVar = [];

for(var x=0;x<4;x++)
{
    boxVar[x] = $("#" + boxFields[x]).val();
}

$.post("url.php",
{
  requestType: "updateRow",
  
  for(var y=0;y<4;y++)
  {
    boxFields[y]: boxVar[y] 
    if(y!=3){,}  
  }
  
  /* I want above code to work like this:
  requestType: "updateRow",
  customerId: 12345,
  customerName: John Doe,
  customerContact: XXXXXXXXXX,
  customerEmail: xxxxxx@xxx.com
  */
},
function(data)
{
 //Success Code Lines..........
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<input type="text" id="customerId" value="12345"/>
<br>
<br>
<input type="text" id="customerName" value="John Doe"/>
<br>
<br>
<input type="text" id="customerContact" value="XXXXXXXXXX"/>
<br>
<br>
<input type="text" id="customerEmail" value="xxxxxx@xxx.com"/>

Also would like to know how to prevent from getting SQL Injection

Thank You!

</div>
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2条回答

  • doutao5419 doutao5419 5年前

    Could i use for loop to create dynamic objects inside $.post.

    Not inside the call to .post(), no. Which has nothing to do with .post() itself or with AJAX or anything like that, but simply as the syntax of the language. Consider your attempt:

    $.post("url.php",
    {
      requestType: "updateRow", 
      for(var y=0;y<4;y++)
      {
        boxFields[y]: boxVar[y] 
        if(y!=3){,}  
      }
      //...
    

    The second argument to the function is simply an object. And things like loops and other control structures aren't valid for declaring an object. What you can do is, well, what you already did before. Build the object, then use it in the function call:

    var someArray = [];
    for(var x = 0; x < 4; x++)
    {
        someArray[x] = someValue;
    }
    // etc.
    
    // later...
    $.post('url.php', someArray, function () { /.../ });
    

    Basically, a loop is not an object that can be passed to a function. It's a control structure for imperative code.

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  • dongyao4419 dongyao4419 5年前

    You cannot put a loop inside your post function (a loop is not an object), but you can construct your data before the post. The cleaner way to go is this one:

    var data = {
      requestType: "updateRow"
    };
    
    $('input').each(function() { // change the selector to be more precise
      data[$(this).attr('id')] = $(this).val();
    });
    
    console.log(data);
    
    $.post("url.php", data, function(data) {
      //Success Code Lines..........
    });
    

    SQL injection

    Even if you can do some checking in JS, the only way to really prevent SQL injection is to escape/check/use special methods on the server side, when it interacts with an SQL database.

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