stata如何将因变量转换为因子变量

Question

//Calculate ILR: Use permutation of sleep awake sed lpa mvpa
//Sleep outcome
gen ilr_sleep_sleep=(sqrt(3/4))*ln(sleep_min/((sed_min*lpa_min*mvpa_min)^(1/3)))
gen ilr_sleep_sed=(sqrt(2/3))*ln(sed_min/((lpa_min*mvpa_min)^(1/2)))
gen ilr_sleep_lpa=(sqrt(1/2))*ln(lpa_min/mvpa_min)
//Sed outcome
gen ilr_sed_sed=(sqrt(3/4))*ln(sed_min/((lpa_min*mvpa_min*sleep_min)^(1/3)))
gen ilr_sed_lpa=(sqrt(2/3))*ln(lpa_min/((mvpa_min*sleep_min)^(1/2)))
gen ilr_sed_mvpa=(sqrt(1/2))*ln(mvpa_min/((sleep_min)))
//Lpa outcome
gen ilr_lpa_lpa=(sqrt(3/4))*ln(lpa_min/((mvpa_min*sleep_min*sed_min)^(1/3)))
gen ilr_lpa_mvpa=(sqrt(2/3))*ln(mvpa_min/((sleep_min*sed_min)^(1/2)))
gen ilr_lpa_sleep=(sqrt(1/2))*ln(sleep_min/((sed_min)))
//MVPA outcome
gen ilr_mvpa_mvpa=(sqrt(3/4))*ln(mvpa_min/((sleep_min*sed_min*lpa_min)^(1/3)))
gen ilr_mvpa_sleep=(sqrt(2/3))*ln(sleep_min/((sed_min*lpa_min)^(1/2)))
gen ilr_mvpa_sed=(sqrt(1/2))*ln(sed_min/lpa_min)
 
//Sleep
mixed yuwen i.sex age fa ma income bmi ilr_sleep_sleep ilr_sleep_sed ilr_sleep_lpa || grade: || nclass:
//Calculate ILR: Use permutation of sleep awake sed lpa mvpa
**depvar may not be a factor variable**

Answer 1

参考GPT和自己的思路：要将因变量转换为因子变量，可以使用Stata中的“factor variable”命令。在这种情况下，您可以在命令后面添加一个“if”语句来选择要转换的变量。例如，在您的代码中，要将“depvar”变量转换为因子变量，您可以使用以下命令：

factor depvar, if(depvar)

这将将“depvar”变量从数值变量转换为因子变量。请确保在使用此命令之前，您已经将其整理为离散值，以便正确地转换为因子变量。