dongyirong3564 2017-07-29 20:19
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如果DB表中存在数据,如何更新[重复]

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  if (isset($_POST["sendComments"]) ) {
    $whichProjectToSave= mysqli_real_escape_string($db5, $_POST['whichProjectToSave']);
    $commentsToPHP= mysqli_real_escape_string($db5, $_POST['commentsToPHP']);
    $objectName= mysqli_real_escape_string($db5, $_POST['objectName']);
    $sql="INSERT INTO   objectsCommentsTable (objectsCommentsText,projectName,objectName) VALUES('$commentsToPHP','$whichProjectToSave','$objectName')";
    // $sql="UPDATE objectsCommentsTable  SET objectsCommentsText ='$commentsToPHP'  WHERE projectName= '$whichProjectToSave' AND objectName = '$objectName' ";
   mysqli_query($db5,$sql);
                                  }

I have to update if data exists. But i know only how to use method above. Actually i can only insert data in table as first and then update it with changing of code. But i would like to use something like in code below. How can it be performed?

 IF EXISTS ( SELECT objectsCommentsText FROM objectsCommentsTable  WHERE objectName='$objectName' AND projectName = '$projectName')
    UPDATE objectsCommentsTable
    SET objectsCommentsText ='$commentsToPHP'
    WHERE projectName= '$whichProjectToSave' AND objectName = '$objectName' 
ELSE 
  INSERT INTO   objectsCommentsTable (objectsCommentsText,projectName,objectName) 
  VALUES('$commentsToPHP','$whichProjectToSave','$objectName')
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  • dongtiaobeng7901 2017-07-29 20:26
    关注

    First, add unique index:

    ALTER TABLE objectsCommentsTable ADD UNIQUE project_object_unique (projectName, objectName);
    

    This will prevent adding rows with same projectName and objectName, and make ON DUPLICATE work.

    Then, you can edit your query to use ON DUPLICATE

    INSERT INTO objectsCommentsTable
    (objectsCommentsText, projectName, objectName) VALUES ('$commentsToPHP','$whichProjectToSave', '$objectName')
    ON DUPLICATE KEY
       UPDATE objectsCommentsText='$commentsToPHP'
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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