2014-12-30 13:56
浏览 46


How to fetch the data from the php using json in phonegap, On server xampp, I just write the following code replay.php. I have taken these example from this line and and I want to mention this question from stackover flow, try to make according to it but my android emulator is not resounding, please help me on this topic, I am new in phonegap and android,


header('Content-Type: application/json');
$choice =$_POST["button"];
$cars = array("Honde", "BMW" , "Ferrari");
$bikes = array("Ducaite", "Royal Enfield", "Harley Davidson");
if($choice == "cars") print json_encode($cars);
print json_encode($bikes);

In eclipse I write the following code in index.html

<!DOCTYPE html>
    <script charset="utf&minus;8" type="text/javascript">
    function connect(e)
        var term= {button:e};
        alert("no connection");},
                for(var i in data){
    <center><b>Bikes or Cars</b></center>
    <center><input onclick="connect(this.value)" type="button" value="cars" /></center>
    <center><input onclick="connect(this.value)" type="button" value="bikes" /></center>
    <ul id="result"></ul>

图片转代码服务由CSDN问答提供 功能建议

如何使用phonegap中的json从 php获取数据, 服务器xampp ,我只需编写以下代码 replay.php 。 我从这一行和我想提及来自堆栈流程的这个问题 ,尝试根据它制作,但我的机器人模拟器没有响亮,请帮助我这个主题,我是新的 phonegap和android,

重播 .php

header('Content-Type:application / json'); 
 $ choice = $ _ POST [“button”]  ; 
 $ cars = array(“Honde”,“BMW”,“Ferrari”); 
 $ bikes = array(“Ducaite”,“Royal Enfield”,“Harley Davidson”); 
if($ choice ==  “cars”)打印json_encode($ cars); 
print json_encode($ bikes); 

在eclipse中我写下面的内容 代码 index.html

 &lt;!DOCTYPE html&gt; 
&lt; html&gt; 
&lt; head&gt; 
&lt; script  charset =“utf&amp; minus; 8”type =“text / javascript”&gt; 
 function connect(e)
 var term = {button:e}; 
 $ .ajax({
 url:  'http://localhost/Experiements/webservices/reply.php',
 error:function(jqXHR,text_status,strError)  {
 alert(“no connection”);},
 for(var i 在数据中){
 $(“#result”)。append(“&lt; li&gt;”+ data [i] +“&lt; / li&gt;”); 
&lt; / script&gt; 
&lt; / head&gt; 
&lt; body&gt; 
&lt; center&gt;&lt; b&gt;自行车或汽车&lt; / b&gt;&lt; / center&gt; 
&lt; center&gt;&lt;输入 onclick =“connect(this.value)”type =“button”value =“cars”/&gt;&lt; / center&gt; 
&lt; center&gt;&lt; input onclick =“connect(this.value)”type =“ 按钮“value =”bikes“/&gt;&lt; / center&gt; 
&lt; center&gt;&lt; b&gt;结果&lt; / b&gt;&l  t; / center&gt; 
&lt; ul id =“result”&gt;&lt; / ul&gt; 
&lt; / body&gt; 
&lt; / html&gt; 
  • 点赞
  • 写回答
  • 关注问题
  • 收藏
  • 邀请回答

1条回答 默认 最新

  • duancheng3342 2014-12-30 21:20

    Correct me if I am wrong but you are just asking HOW to perform this process, correct? Your question sounds like that code is from a "tutorial" and not your application? Below is how I have performed this function in one of my own private apps using PhoneGap.

    My AJAX call looks like this, minus custom data manipulations:

        url: "",    // path to remote script
        dataType: "JSON",                                // data set to retrieve JSON
        success: function (data) {                       // on success, do something...
            // grabbing my JSON data and saving it
            // to localStorage for future use.
            localStorage.setItem('myData', JSON.stringify(data));

    My PHP script functions like so:

    // PHP headers (at the top)
    header("Access-Control-Allow-Origin: *");
    header("Content-Type: application/json");
    // connect to your database and perform your query    
    // then build your output...
    while($row = mysqli_fetch_array($result)) {
        $output[] = array (
            "id" => $row['id'],
            "firstname" => $row['firstname'],
            "lastname" => $row['lastname']
    echo json_encode($output);

    This process above will give you a saved localStorage file of the data from the PHP Script (your database). You can then use the localStorage to output your data without having to continually perform AJAX requests.

    For example:

    var myData = JSON.parse(localStorage.getItem('myData'));
    var i;
    for (i = 0; i < myData.length; i = i + 1) {
       console.log(myData[i].firstname);      // this should output the firstnames.
    点赞 打赏 评论

相关推荐 更多相似问题