douxing8323 2012-10-20 08:42
浏览 10
已采纳

同时为什么在这种情况下价值会发生变化?

when you try this code the result is ... The number is 1

<?php
$i=1;
do
  {

  echo "The number is " . $i . "<br />";
    $i++;

  }
while ($i==10);
?>

but when you change this code to be like this the result is 2

<?php
$i=1;
do
  {

    $i++;
      echo "The number is " . $i . "<br />";


  }
while ($i==10);
?>

so why the result changed ..?

  • 写回答

4条回答 默认 最新

  • douhuanchi6586 2012-10-20 08:46
    关注

    $i++; is post increment operator so it will increment value by 1 on next line and it use same value on current line

    First Case: you are doing echo $i and then doing increment

    Second Case: you are incrementing $i++ before echo statement so by nature it will increase value by 1 on echo line

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(3条)

报告相同问题?

悬赏问题

  • ¥35 MIMO天线稀疏阵列排布问题
  • ¥60 用visual studio编写程序,利用间接平差求解水准网
  • ¥15 Llama如何调用shell或者Python
  • ¥20 谁能帮我挨个解读这个php语言编的代码什么意思?
  • ¥15 win10权限管理,限制普通用户使用删除功能
  • ¥15 minnio内存占用过大,内存没被回收(Windows环境)
  • ¥65 抖音咸鱼付款链接转码支付宝
  • ¥15 ubuntu22.04上安装ursim-3.15.8.106339遇到的问题
  • ¥15 blast算法(相关搜索:数据库)
  • ¥15 请问有人会紧聚焦相关的matlab知识嘛?