doulongsi1831 2013-09-25 18:51
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Mysql获取返回nil值的用户数据

I recently received -3 ratings for my recent question though the solution wasn't provided. My apologies if I posted something which I shouldn't have.

Alright so it is related to that ques only I have this code:

$data = mysql_connect("localhost", "user", "pass");
mysql_select_db("dbname");
$data = mysql_query("SELECT `location` FROM `upload` WHERE `name` = '".$result['name']."'")
or die(mysql_error());  
$info = mysql_fetch_array( $data );
$display_url = $info['createlink'];

So when I echo $display_url it returns nil value and in db I checked the createlink field and the value stored there is a link. And when I use

$display_url = $info['location'];

It returns perfect value.

~~The field at createlink contains 'http://www.exdomain.com/create/create.php?t=BATMAN_SLAPPING_ROBBIN.jpg'

~~The field at location contains 'http://www.exdomain.com/create/img/BATMAN_SLAPPING_ROBBIN.jpg'

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1条回答 默认 最新

  • douhui4699 2013-09-25 18:57
    关注

    You're not requesting the createlink field from the table, only location. Change your query to this:

    $data = mysql_query("SELECT `location`,`createlink` FROM `upload` WHERE `name` = '".$result['name']."'")
    

    You should also move away from the deprecated mysql_* functions and switch to PDO/mysqli so that your code will work in future versions of php. This will also allow you to parametrize your queries to prevent SQL injection.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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