PHP time（）函数返回epoch而不是当前时间

Question

I have the following php code that is meant to format the current date and time:

$rawdatetime = time();
$datetime = date('Y-m-d', $rawdatetime) . 'T' . date('H:i:s', $rawdatetime) . '.000Z';
$this->debug($datetime);

The formatting seems to be working fine, but it keeps outputting that it is 1970; I get the following output:

1970-01-01T00:00:00.000Z

My guess is that my server is not configured properly, but my Google search has not given me any clues. I am running WAMP if it helps.

Thanks in advance for any advice you may have.

EDIT: it seems that the date and time functions are working properly; but assigning them to a variable is what is the problem. Any work arounds to get the same formatting as above would be welcomed. But I would also like to know why this problem is happening.

Answer 1

Firstly, you don't need to use time() at all here, because date() will use the current time as the default value if you don't pass a value to that parameter.

Secondly, you're using two separate date() calls, separated by a "T". Note that the formatting for date() can accept a hard-coded character like T; you just need to escape them with backslashes, so you don't need to split it into two function calls.

Your entire code could look like this:

$datetime = date('Y-m-d \T H:i:s.\0\0\0\Z');

Which gives 2013-06-19 T 11:18:53.000Z