PHP显示名称相同的最后数据

Question

How to display last data where name is same. I think my $result is wrong. Please help me solve it. Thank you

$SearchQ = "SELECT * FROM tblperson where Id = ".$_GET['Id'];
$SearchResult = mysql_query($SearchQ,$link);
$StaffRec = mysql_fetch_array($SearchResult);

<input type="text" name="txtPastDate" id="txtPastDate" value="<?php 
    $result = mysql_query("SELECT * from tblvisit order by tblvisit.Id desc limit 1 where tblvisit.PatientName = $StaffRec['Name']");
    while($row = mysql_fetch_assoc($result))
    {
        echo $row['VisitDate'];
    }
    mysql_free_result($result);
?>"/>

Answer 1

Your query would be

$result = mysql_query("SELECT * from tblvisit 
                       WHERE tblvisit.PatientName = '".$StaffRec['Name']."'
                       ORDER BY tblvisit.Id desc limit 1");

After the condition only you have to apply the order.