如何将[]字符串转换为[]命名字符串

Question

In go I have a named type

type identifier string

I am using a standard library method that returns []string and I want to convert that into []identifier. Is there a smoother way to do that other than:

...
stdLibStrings := re.FindAllString(myRe, -1)
identifiers := make([]identifier, len(stdLibStrings))
for i, s := range stdLibStrings {
    identifiers[i] = identifier(s)
}

My end goal is to have this named identifier type have some methods which, if I'm not mistaken, require a named type versus using a unnamed type as a receiver which isn't allowed.

Thanks.

Answer 1

The Go Programming Language Specification

Assignability

A value x is assignable to a variable of type T ("x is assignable to T") in [this case]:

x's type V and T have identical underlying types and at least one of V or T is not a named type.

For example,

package main

import "fmt"

type Indentifier string

func (i Indentifier) Translate() string {
    return "Translate " + string(i)
}

type Identifiers []string

func main() {
    stdLibStrings := []string{"s0", "s1"}
    fmt.Printf("%v %T
", stdLibStrings, stdLibStrings)
    identifiers := Identifiers(stdLibStrings)
    fmt.Printf("%v %T
", identifiers, identifiers)
    for _, i := range identifiers {
        t := Indentifier(i).Translate()
        fmt.Println(t)
    }
}

Output:

[s0 s1] []string
[s0 s1] main.Identifiers
Translate s0
Translate s1