The methods appear to be hidden, because the function takes an interface type. The interface of http.ResponseWriter
does not define the Hijack()
method. This is defined in the http.Hijacker
interface. A concrete type may implement multiple interfaces. But even if such concrete type is passed into a scope where its type definition is an interface, additional methods will not be accessible. So in the questioned example, type assertion is performed to make make the Hijack()
method available.
Some examples (playground):
package main
import (
"fmt"
)
type Ship interface {
Load(containers []string)
Condition() []string
}
type Sea interface {
Draft() int
}
// seaShip implements the Sea and Ship interfaces
type seaShip struct {
containers []string
}
// Load is only part of the Ship interface
func (ss *seaShip) Load(containers []string) {
ss.containers = append(ss.containers, containers...)
}
// Condition is only part of the Ship interface
func (ss *seaShip) Condition() []string {
return ss.containers
}
// Draft is only part of the Sea interface
func (ss *seaShip) Draft() int {
return len(ss.containers)
}
// Pirates is not defined in any interface and therefore can only be called on the concrete type
func (ss *seaShip) Pirates() string {
return "Help!"
}
// NewShip returns an implementation of the Ship interface
func NewShip() Ship {
return &seaShip{}
}
func main() {
ship := NewShip()
ship.Load([]string{"Beer", "Wine", "Peanuts"})
fmt.Println(ship.Condition())
// Won't compile, method is not part of interface!
// fmt.Println(ship.Draft())
// Assert to make Draft() available
sea := ship.(Sea)
fmt.Println(sea.Draft())
// Won't compile, methods are not part of interface!
// fmt.Println(sea.Condition())
// fmt.Println(sea.Pirates())
// Assert to the concrete type makes all methods available
ss := sea.(*seaShip)
fmt.Println(ss.Condition())
fmt.Println(ss.Pirates())
}