一道C++编程设计，搞不明白

Question

设计一个程序,包含公司类( company )和员工类( employee ),其中:
1)一个公司有5名员工:2)公司有名字、类型、地址等属性;3)公司具有对外宣传、外派员工等行为:4)员工有姓名、职位、性别、年龄、工号,是否打卡等属性:5)员工具有完成工作、打卡等行为:6完成主函数的编写,并在主函数中完成 company 对外宜传和外派员工等工作。

Answer 1

代码如下，如有帮助，请帮忙采纳一下，谢谢。

#include <iostream>
#include <string>
using namespace std;

class employee
{
private:
    string mName;
    string mZw;  //职位
    string mSex;
    int mAge;
    string mNmb; //工号
public:
    employee(){}
    employee(string name,string zw,string sex,int age,string id){
        mName = name; 
        mZw = zw;
        mSex = sex;
        mAge = age;
        mNmb = id;
    }
    void work(){
        cout << mName << "正在工作"<<endl;
    }
    void card(){
        cout << mName << "打卡" <<endl;
    }
    
    //get an set
    void setName(string s){mName = s;}
    void setZw(string s){mZw = s;}
    void setSex(string s){mSex = s;}
    void setAge(int a){mAge = a;}
    void setNmb(string nmb){mNmb = nmb;}

    string getName(){return mName;}
    string getZw(){return mZw;}
    string getSex(){return mSex;}
    int getAge(){return mAge;}
    string getNmb(){return mNmb;}
};

class company 
{
private:
    employee mEmp[5];
    string mName;
    string mType;
    string mAddr;
    int nNmb;
public:
    company(){nNmb = 0;}
    void xuchuan(){
        cout << mName << "是个好公司"<<endl;
    }
    void waipai()
    {
        int n,i;
        cout << "请输入外派员工的数量：";
        cin >> n;
        if (n>5)
        {
            cout << "公司没有那么多人"<<endl;
            return ;
        }
        cout << "外派人员："<<endl;
        for(i=0;i<n;i++)
        {
            cout << "  姓名：" << mEmp[i].getName() <<  "  年龄：" << mEmp[i].getAge()<<endl;
        }
    }
    //
    void setName(string s){mName = s;}
    void setType(string t){mType = t;}
    void setAddr(string addr){mAddr = addr;}
    void setEmp(employee a[],int n)
    {
        nNmb = n;
        for(int i = 0;i<n;i++)
            mEmp[i] = a[i];
    }

    string getName(){return mName;}
    string getType(){return mType;}
    string getAddr(){return mAddr;}
    void getEmp(employee a[],int &nmb)
    {
        for(int i = 0;i< nNmb;i++)
            a[i] = mEmp[i];
    }
    void addEmp(employee e)
    {
        if(nNmb < 5)
        {
            mEmp[nNmb] = e;
            nNmb++;
        }
    }
};




int main()
{
    employee a1("张一","经理","男",33,"00001");
    employee a2("张二","经理","男",34,"00002");
    employee a3("张三","经理","男",35,"00003");
    employee a4("张四","经理","男",36,"00004");
    employee a5("张五","经理","男",37,"00005");
    company cp;
    cp.setName("搞笑有效公司");
    cp.setType("娱乐");
    cp.setAddr("远在天边");
    cp.addEmp(a1);
    cp.addEmp(a2);
    cp.addEmp(a3);
    cp.addEmp(a4);
    cp.addEmp(a5);
    cp.xuchuan();
    cp.waipai();
    return 0;
}