array：如何返回引用/指针

Question

Hy everybody!

how to return an array reference / pointer in a function?

ex:

$a=array('given'=>array());

function getRef(&$ref){

//adds a child element to the given reference/pointer
$ref['test']=array();

//doesn't return the current reference/pointer
return $ref['test'];
}

//out: Array ( [given] => Array ( [test] => Array ( ) ) )
$p=getRef($a['given']);
print_r($a);

//out: same as above
//expected: ( [given] => Array ( [test] => Array ([test2] => Array ( ) ) ) )
$p['test2']=array();
print_r($a);

Thanks!

Answer 1

Maybe something like this:

$a=array('given'=>array());

function getRef(&$ref){

//adds a child element to the given reference/pointer
$ref['test']=array();

//doesn't return the current reference/pointer
return $ref['test'];
}

//out: Array ( [given] => Array ( [test] => Array ( ) ) )
$p=getRef($a['given']);
print_r($a);

//out: same as above
//expected: ( [given] => Array ( [test] => Array ([test2] => Array ( ) ) ) )
$p['given']['test']['test2']=array();
print_r($p);